Thủ Thuật về Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively Chi Tiết
Lê Khánh Vy đang tìm kiếm từ khóa Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively được Cập Nhật vào lúc : 2022-10-03 22:08:09 . Với phương châm chia sẻ Thủ Thuật về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi đọc Post vẫn ko hiểu thì hoàn toàn có thể lại Comment ở cuối bài để Tác giả lý giải và hướng dẫn lại nha.Try the new Google Books
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TCS Programming and Technical Numerical Ability LCM and HCF
- Hcf ( (148-4), (246-6), (623-11))=126 years agoHelpfull: Yes(9) No(5) 148-4=144 246-6=240 623-11=612
Hence these 3 are divided by 12 leaving remainders 4 6 and 11
6 years agoHelpfull: Yes(6) No(0) hcf of 144, 240,612 is 12. 12 is the answer6 years agoHelpfull: Yes(2) No(1) difference of the dividend and remainder gives you the divisible number so Hcf of ((148-4),(246-6),(623-11) 144=12*12 240=12*20 623=12*51so the HCF is 12.
5 years agoHelpfull: Yes(2) No(0) hcf of given numbers is 126 years agoHelpfull: Yes(0) No(0) a*4/100=8 , a=800/4, a=200 b*8/100 , b=400/8, b=50
c=50/200, c=1/4
5 years agoHelpfull: Yes(0) No(2) 148-4=144 246-6=240 623-11=612Hence these 3 are divided by 12 leaving remainders 4 6 and 11
3 years agoHelpfull: Yes(0) No(0) Ans2 148-4=144 246-6=240 623-11=612 144-= 2*2*18 240= 2*2*3*20 612=2*2*2 great no
3 years agoHelpfull: Yes(0) No(0) We know that When a greatest number that divide x,y,z and leaves remainder a,b,c respectively = HCF of (x - a),(y - b),(z - c). Now, HCF of (148 - 4),(246 - 6),(623 - 11) = > HCF of (144, 240,612) Prime factorization of 144 = 2 * 2 * 2 * 2 * 3 * 3 Prime factorization of 240 = 2 * 2 * 2 * 2 * 3 * 5 Prime factorization of 612 = 2 * 2 * 3 * 3 * 17 HCF(144,240,612) = 2 * 3 * 3 = 12. Hence, the greatest number is n = 12. Now, We have to find the remainder when n is divided by 7. = > 7)12(1 7 --- 5.Therefore, the remainder is 5.
3 years agoHelpfull: Yes(0) No(0) 148-4=144,246-6=240,623-11=612HCF of 144,240,612 is 12.2 years agoHelpfull: Yes(0) No(0)
Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively ?
Remainder in case of 148 = 4 Number = 148 – 4 = 144 Remainder in case of 246 = 6 Number = 246 – 6 = 240 Remainder in case of 623 = 11 Number = 623 – 11 = 612
Now, we have find the H.C.F. of 144, 240 and 612
H.C.F. of 144, 240 and 612 = 2 * 2 * 3 = 12
Therefore, the required number is 12 that will divide 148, 246 and 623 leaving remainders 4, 6 and 11 respectively.
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What is the greatest number that will divide 148 246 and 623?
∴ The required number is 12.What is the greatest number that will divide 2400 and 1810 and leave remainders 6 and 4 Respectively?
The required number is 42. Tải thêm tài liệu liên quan đến nội dung bài viết Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively